14*q^2-(29*q-12)=0

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Solution for 14*q^2-(29*q-12)=0 equation:


Simplifying
14q2 + -1(29q + -12) = 0

Reorder the terms:
14q2 + -1(-12 + 29q) = 0
14q2 + (-12 * -1 + 29q * -1) = 0
14q2 + (12 + -29q) = 0

Reorder the terms:
12 + -29q + 14q2 = 0

Solving
12 + -29q + 14q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(4 + -7q)(3 + -2q) = 0

Subproblem 1

Set the factor '(4 + -7q)' equal to zero and attempt to solve: Simplifying 4 + -7q = 0 Solving 4 + -7q = 0 Move all terms containing q to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -7q = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -7q = 0 + -4 -7q = 0 + -4 Combine like terms: 0 + -4 = -4 -7q = -4 Divide each side by '-7'. q = 0.5714285714 Simplifying q = 0.5714285714

Subproblem 2

Set the factor '(3 + -2q)' equal to zero and attempt to solve: Simplifying 3 + -2q = 0 Solving 3 + -2q = 0 Move all terms containing q to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2q = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2q = 0 + -3 -2q = 0 + -3 Combine like terms: 0 + -3 = -3 -2q = -3 Divide each side by '-2'. q = 1.5 Simplifying q = 1.5

Solution

q = {0.5714285714, 1.5}

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